Question

A car with a weight of 6996 N is subjected to a net force of 1.74e4. The cars acceleration will be

Answer 1

Answer: 24.37 m/s/s [forward] = a

Step-by-step explanation:

First, find mass with the Fgrav formula.

Fgrav=mg

6996=m(9.8)

713.88 kg

Then, plug the answer into Newton's second law formula.

Fnet = ma

1.74e4 = (713.88)a

(1.74e4)/(713.88) = a

24.37 m/s^2 = a