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Solve the system of equations using substitution. 3x + 2y = 7 y = –3x + 11 A. The ordered pair, negative 4, nineteen halves. B. (6, –7) C. (6, –3) D. (5, –4)
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Solve the system of equations using substitution. 3x + 2y = 7 y = –3x + 11

A. The ordered pair, negative 4, nineteen halves.

B. (6, –7)

C. (6, –3)

D. (5, –4)

User Thomas Hunziker
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1 Answer

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3x + 2y = 7
y = –3x + 11

replace y = –3x + 11 into 3x + 2y = 7

3x + 2y = 7
3x + 2(–3x + 11) = 7
3x -6x + 22 = 7
-3x = 7 - 22
-3x = -15
x = 5

y = –3x + 11
y = -3(5) + 11
y = -15 + 11
y = -4

x = 5 and y = -4

answer: D. (5, –4)
User Tropicalista
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