Question

The length of a car is 4.2m,correct to 1 decimal place. Write down the upper bond and the lower bond of the length of this car.​

Answer 1

The upper pound is 4.25 m and the lower bound is 4.15 m

4.15 m ≤ 4.2 m < 4.25 m

Explanation:

Let us solve the question

∵ The length of the car corrected to 1 decimal place

→ 1 decimal place means tenth

∴ It corrected to the tenths place which is 0.1

→ Divide it by 2

∵ 0.1 ÷ 2 = 0.05

∴ The limit is 0.05 m

→ To get the lower bound subtract 0.05 from the length of the car

∵ The length of the care is 4.2 m

∴ The lower bound = 4.2 - 0.05

∴ The lower bound = 4.15 m

→ To get the upper bound add 0.05 to the length of the car

∵ The length of the care is 4.2 m

∴ The upper bound = 4.2 + 0.05

∴ The upper bound = 4.25 m

∴ 4.15 m ≤ 4.2 m < 4.25 m

∴ The upper pound is 4.25 m and the lower bound is 4.15 m

P.s hopes this helps