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23 votes
23 votes
Point M is the midpoint of AB. If AM = b² + 5b and
MB = 3b + 35, what is the length of AM?

User Tobias J
by
3.2k points

1 Answer

21 votes
21 votes

Explanation:

since M is the midpoint, it means that AM = MB.

so,

b² + 5b = 3b + 35

b² + 2b - 35 = 0

the general solution to such a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case (x is called b, don't get confused, as this is not the factor of x) this gives us

b = (-2 ± sqrt(2² - 4×1×-35))/(2×1) =

= (-2 ± sqrt(4 + 140))/2 = (-2 ± sqrt(144))/2 =

= (-2 ± 12)/2 = -1 ± 6

b1 = -1 + 6 = 5

b2 = -1 - 6 = -7

therefore, we have 2 solutions

b = 5

AM = 5² + 5×5 = 25 + 25 = 50

b = -7

AM = (-7)² + 5×-7 = 49 - 35 = 14

control, as AM = MB

MB = 3×5 + 35 = 15 + 35 = 50

or

MB = 3×-7 + 35 = -21 + 35 = 14

AM = MB in both cases, so, all is correct.

User SeanJA
by
3.2k points
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