Question

A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an

angle of 30° above the horizontal. Determine the horizontal component of the applied

force

Answer 1

658.16N

Step-by-step explanation:

Step one:

given data

mass m= 235kg

Force F= 760N

angle= 30 degrees

Required

The horizontal component of the force

Step two:

The horizontal component of the force

Fh= 760cos∅

Fh=760cos30

Fh=760*0.8660

Fh=658.16N