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5 votes
So this has to do with permutations and honestly I need an explanation on how I can figure these out.

So this has to do with permutations and honestly I need an explanation on how I can-example-1
So this has to do with permutations and honestly I need an explanation on how I can-example-1
So this has to do with permutations and honestly I need an explanation on how I can-example-2

1 Answer

5 votes
well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....


u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.



I know this is pretty much confusing ....but still I tried my best....

if anything troubles u here feel free to ask me
User Arturaz
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