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How would you prepare 70.0 ml of 0.200 m hno3 from a stock solution of 5.00 m hno3?

1 Answer

6 votes
70x0.2=5×x
X=2.8 ml
basically for these kind of questions you should use this formula: m1v1= m2v2
m is molar v is volume
User Yoseph
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