Question

A metal stands specifies a maximum load of 450 lb. will it support an aquarium that weighs 59.5 lb and is filled with 37.9 L of seawater (d = 1.03 g/ml)?

Answer 1

Answer: 450 lb > 145.38 lb ,Yes. Metal stand will able to support the aquarium with 37.9 L of water.

Step-by-step explanation:

Maximum load sustained by metal stand = 450 lb

Weight of the aquarium = 59.5 lb

Density of seawater = 1.03 g/mL

Volume of the seawater = 37.9 L = 37900 ml (1 L=1000 mL)

`Density=\frac{\text{mass of water}}{\text{volume of the water}}=1.03 g/mL=(mass)/(37900 mL)`

Mass of the water = 39,037 g = 85.88 lb (1 g = 0.0022 lb)

Load due to aquarium and water on metal stand :

= 59.5 lb + 85.88 lb = 145.38 lb

450 lb > 145.38 lb Yes. Metal stand will able to support the aquarium with 37.9 L of water.

Answer 2

First calculate the corresponding mass of 37.9 L

M = 37.9 L ( 1000 ml / 1 L ) ( 1.03 g / ml)

M = 39,037 g

Convert g to pounds

M = 39,037 g ( 1 lb / 453.592 g)

M = 86.06 lb

Then add the 59.5 ln

M = 86.06 + 59.5 = 145.56 lb so it will support it