1 Answer

Since K Saji · Answer 1 · 2018-10-19T18:31:10+0000

The equation for a parabola with vertex
(h, k)

is

We plug in:

y=a(x-4)^(2)+75

We find

by plugging in the point
(0, 27)

:

$\Rightarrow 27=a(-4)^(2)+75$

$\Rightarrow 27=16a+75$

$\Rightarrow 16a=-48$

$\Rightarrow a=-3$

So our equation is

y=-3(x-4)^(2)+75

To find x-intercepts, we set
y=0

:

$\Rightarrow -3(x-4)^(2)=-75$

$\Rightarrow (x-4)^(2)=25$

$\Rightarrow x-4=5, -5$

$\Rightarrow x=9, -1$

So the x-intercepts are 9 and -1.

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