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If a 500µF can store 0.02J of energy, what must the voltage supplied to the capacitor be

2 Answers

4 votes

Answer:

9 volts

Step-by-step explanation:

User Kasandra
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The energy stored on a capacitor can be expressed in terms of the work done by the battery. Voltage represents energy per unit charge, so the work to move a charge element dq from the negative plate to the positive plate is equal to V dq, where V is the voltage on the capacitor.

U =0.5CV^2

0.02 =0.5(500x10^-6) V^2

Solve for V

V = 8.94 volts

User Ott Toomet
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