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How much work must be done to stop a 925-kg car traveling at 95 km/h?
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37 votes
37 votes
How much work must be done to stop a 925-kg car
traveling at 95 km/h?

User Wxs
by
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1 Answer

18 votes
18 votes
V = 95 km/h = 95/3.6 = 26.39 m/sec

Stored kinetic energy Ek = 1/2mV^2 = 925* 26.39^2/2 = 322,073 joule
User Dharmatech
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