Question

How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? (4 points) You must balance this equation first! H2SO4 + NaOH → H2O + Na2SO4 Show, or explain, all of your work along with the final answer.

Answer 1

Balanced Equation: H2SO4 + 2NaOH --> 2H2O + Na2SO4

Moles= Mass/RMM
= 65.5/40
= 1.6375

Mole Ratio = 2:2
= 1.6375

Mass (H2O) = 1.64 x 18
= 29.5 g