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What are the real root of the given power equation! 3(x-4)4/3 +16=64
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What are the real root of the given power equation! 3(x-4)4/3 +16=64

User Gintas
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3(x-4 ) \frac{4}{3} + 16= 64

The 3's cancel out so the new equation becomes 4(x-4) + 16 = 64

Expand the brackets
4x -16 + 16 = 64
4x=64
x= 16

User Speednet
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