Question

What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.?

Answer 1

Given that u= 40 m/s

we know that if an object is thrown upward its follows the equation
v² = u² - 2gh
0 = (40)²-2×10×h
1600=20h
h=80 m
The maximum height is 80 m

Answer 2

81.63 meters is the maximum height.

Step-by-step explanation:

In order to calculate this you just have to remember the formula for the maximum height in projectile motion, in this case we dont have an angle because it is thrown straight upward, so we ecan take out the sine component of the formula:

`H=(Vo^(2) )/(2g)`

So we just insert our values into the formula:

`H=(Vo^(2) )/(2g)\\H=(40^(2) )/(2(9.8))\\H=(1600 )/(19.6)\\h= 81.63m`

So the maximum height would be 81.63 meters.