Answer:
y = 6(x + 8)² + 4
Explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Using the method of completing the square.
y = 6x² + 96x + 388
The coefficient of the x² term must be 1, so
factor out 6 from 6x² + 96x
y = 6(x² + 16x ) + 388
To complete the square
add/subtract (half the coefficient of the x- term)² to x² + 16x
y = 6(x² + 2(8)x + 64 - 64) + 388
= 6(x + 8)² - 384 + 388
y = 6(x + 8)² + 4 ← in vertex form