Question

A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 meters. Determine the acceleration of the bike.

Answer 1

a = 0.712 m/s2

Step-by-step explanation:

Given:

vi = 0 m/s

vf = 7.10 m/s

d = 35.4 m

Find:

a = ??

vf2 = vi2 + 2*a*d

(7.10 m/s)2 = (0 m/s)2 + 2*(a)*(35.4 m)

50.4 m2/s2 = (0 m/s)2 + (70.8 m)*a

(50.4 m2/s2)/(70.8 m) = a

a = 0.712 m/s2

Answer 2

v^2 = 2ax
(7.10 m/s)^2 = 2a(35.4 m)
a = (7.10 m/s)^2 / (2•35.4 m)
= 0.712 m/s^2