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25 votes
25 votes
a herd of 55 cows eat 3250 pounds of silage daily . if the herd size increases to 80 cows how much more will be needed daily ?

User Matt Burnell
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1 Answer

13 votes
13 votes

Answer:

1,475 lbs.

Step-by-step explanation:

Divide the current amount of silage eaten by the current amount of cows to find how much food one cow eats:

3250 ÷ 55 = 59

Then, subtract the current herd size from the new herd size to find how many new cows will be added to the herd:

80 - 55 = 25

Now, multiply the amount of new cows by the amount of silage eaten per cow:

25 * 59 = 1,475

There will need to be 1,475 more pounds of silage daily.

User Baxang
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