Question

1. Use the quadratic formula to solve the equation. -2x^2+3x+5=0

Answer 1

The formula for the solution is:

`x=(-b \pm √(b^2 - 4ac))/(2a)`

In your case: a=-2, b=3, c=5

Replace these in the formula and you'll get:

`x_1=(-b + √(b^2 - 4ac))/(2a)=(-3 + √(3^2 - 4 \cdot (-2) \cdot 5))/(2 \cdot (-2))=-1`

`x_2=(-b - √(b^2 - 4ac))/(2a)=(-3 - √(3^2 - 4 \cdot (-2) \cdot 5))/(2 \cdot (-2))= (5)/(2)`

So you have two roots:
x1 = -1
x2 = 5/2

Answer 2

The answer is x= 5/2 or -1