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The sum of the interior angles of an n-gon is _____(n - 2).

360°
180°
270°
540°

User Kamesha
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6.8k points

2 Answers

2 votes
the sum of the interior angles is 180°
User Paulbullard
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4 votes

The sum of the interior angles of an n-sided polygon can be calculated using formula


\Sigma =(n-2)\cdot 180^(\circ).

It is easy to verify:

1. If n=3 (the smallest possible number of sides for polygon), then the polygon is triangle and the sum of the measures of interior angles of triangle is always 180° .

2. If n>3, draw (n-3) diagonals from one vertex. This diagonals partition the polygon into (n-2) triangles. Thus, the sum of the interior angles of an n-sided polygon is equal to the sum of the measures of interior angles of (n-2) triangles that is


\Sigma =(n-2)\cdot 180^(\circ).

Answer: correct choice is B

User Steve Miskiewicz
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6.0k points
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