Question

how many grams of hydrogen peroxide (H2O2) must be added to 1,500 ml of water to produce a concentration of 1.33m (molai solution)

Answer 1

Data:
m (mass) = ?

MM (Molar Mass) of H2O2
H = 2*1 = 2u
O = 2*16 = 32u
----------------------
MM H2O2 = 34 g/mol

M (molarity) = ?
V = 1500mL → V = 1,5 L
n (molar solution) = 1,33 mol

`M = (n)/(V) = (1,33)/(1,5)`

`M\approx0,8mol/L`

Soon:


`M = (m)/(MM*V)`


`0,8 = (m)/(34*1,5)`

`0,8 = (m)/(51)`

`m = 0,8*51`

`\boxed{m = 40,8g}`