Question

Which point lies outside the circle with equation (x - 2)2 + (y + 3)2 = 4?

(1, -4)

(0, -3)

(2, 0)

(2, -4)

Answer 1

The only point outside of the line is (2, 0)

In order to find if a point is outside, inside or on the line, you simply have to put the number into the equation. If the result is both sides are equal, then it is on the line. If the left side is bigger than the right side, then it is outside of the line. If the right side is bigger than the left, then it is inside of the line. So lets plug in and see where (2, 0) falls.

(x - 2)^2 + (y + 3)^2 = 4

(2 - 2)^2 + (0 + 3)^2 = 4

0^2 + 3^2 = 4

0 + 9 = 4

9 = 4

Since the left side is bigger than the right, we know it is outside of the line

Answer 2

Graphing the circle and the points shows that the point that lies outside the circle is ...
(2, 0)