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Boti · Answer 1 · 2019-07-14T18:08:07+0000

We take the equation
x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0
(x-2)^2 - 4 + (y+3)^2 - 9 = -12
(x-2)^2+ (y+3)^2 = 1
Therefore the answer is (x-2)^2+ (y+3)^2 = 1

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