The given equation is :

Let

The given equation reduces to :

Factoring the equation we have:
(y-7)(y+2)=0
Solving the equations for y:
y-7=0 y+2=0
Or y=7. Or y=-2.
Substituting y value:

Or x=+2.64,-2.64. Square root of negative number is not real. x=

X= -2.64,+2.64,
