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3 votes
Factor completely:

x^40–x^20
y^24+y^8
a^20–a^10+a^5
b^60+b^40–b^20

(^=to the power of)

User Bradmo
by
7.2k points

1 Answer

1 vote
1) x^40–x^20 = x^20(x^20 - 1)

2) y^24+y^8 = y^8(y^16 + 1)

3) a^20–a^10+a^5 = a^5(a^15 - a^5 + 1)

4) b^60+b^40–b^20 = b^20(b^40 + b^20 - 1)

Hope this helps!
User Siwalikm
by
7.1k points
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