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Choose the correct conic section to fit the equation. x^2/36-y^2=1 Circle Ellipse Parabola Hyperbola

2 Answers

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Think its hyperbola. Dont quote me.
User Sereena
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2 votes

Choose the correct conic section to fit the equation. x^2/36-y^2=1 Circle Ellipse Parabola Hyperbola

Solution:

The general equation of circle is:-

(x-h)²+(y-k)=r²

The general equation of ellipse is:-


((x-h)^(2))/(a^(2))+\frac{(y-k)^(2)}{{b^(2)}}=1

The general equation of parabola is:-

y = a(x-h)²+k

The general equation of hyperbola is:-


((x-h)^(2))/(a^(2))-\frac{(y-k)^(2)}{{b^(2)}}=1

The equation of conic section is: x^2/36-y^2=1


((x-0)^(2))/(36)-((y-0)^(2))/(1)}=1


((x-0)^(2))/(6^(2))-\frac{(y-0)^(2)}{{1^(2)}}=1

Hence, this is hyperbola.

Answer: Hyperbola Option (D)

User Shui
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