Question

What is the frequency corresponding to a period of 8.01 s?

Answer 1

The frequency of an oscillation is equal to the reciprocal of the period:

`f= (1)/(T)`
where
f is the frequency
T is the period

In our problem, the period is T=8.01 s, therefore the corresponding frequency is

`f= (1)/(8.01 s)=0.12 s^(-1) = 0.12 Hz`