Question

A sample of O2 occupies a volume of 600 mL. If the pressure exerted on the O2 is tripled with the temperature remaining constant, the new volume of the oxygen is

Answer 1

For 1 mole of an ideal gas, we have PV=RT............(Eq. 1)
where, P = pressure
V= volume
R = universal gas constant
T = Temperature

Let, P1, V1 and T1 be initial pressure, volume and temperature of
`O_(2)` respectively

Let, P2, V2 and T2 be pressure, volume and temperature of
`O_(2)` respectively, after application of pressure.

Using Eq. 1 we get,
`(P1V1)/(P2V2) = (T1)/(T2)` ....... (Eq. 2)

Now, since that T1=T2 and P2=3(P1)

∴ Eq. 2 becomes P1V1=P2V2
∴
`(V2)/(V1) = (P1)/(P2) = (1)/(3)`
∴ V2 =
`(1)/(3)` V1

Thus, final volume V2 will be 1/3 of initial volume V1