Question

A small car with a mass of 800kg moving with a velocity of 27.8 m/s. The car stops at a yellow light in 3.9 seconds. What force did it take for the car to stop?

Answer 1

F = 5702.56 N

Step-by-step explanation:

Given that,

Mass of a small car, m = 800 kg

Initial speed of the car, u = 27.8 m/s

Final speed, v = 0

Time, t = 3.9 s

We need to find the force did it take for the car to stop.

The force acting on an object is given by :

`F=ma\\\\F=(m(v-u))/(t)\\\\F=(800* (0-27.8))/(3.9)\\\\F=-5702.56\ N`

So, the magnitude of force acting on the car to stop is 5702.56 N.