Answer:
I hope it helps U
Explanation:
As given quadratic equation is ,
y= 4x*2 -16x+10
As general quadratic equation is,
y=ax^2+bx+c , we get a=4 , b=-16 , c=10
as a=4 and +ive so the parabola is up-down facing
vertex formula is X(vertex)= -b/2a putt values in this formula we will get x -coordinate of vertex,
X(vertex)= -(-16)/2*4
X(vertex)= 2
Now to find the Y- Co-ordinate just plug in the value of X in the given equation, hence
Y(vertex)=4(2)^2-16*2+10
Y(vertex)=-6
hence the vertex of given equation is (2,-6)