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Find the value of the lesser root of x 2-8x+7=0

User Andy Smith
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Hi there! The answer is x = 1


{x}^(2) - 8x + 7 = 0


(x - 7)(x - 1)
Rule AB = 0, gives A = 0 or B = 0


x - 7 = 0 \: \: or \: \: x - 1 = 0 \\ x = 7 \: \: \: \: \: \: \: \: \: or \: \: x = 1
Therefore, the smallest of both roots is x = 1.
User Miklos
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