Question

A businessman has 10 employees; his salary is equal to 6 times the average of employees' salary. If the 11 of them received a total of 64000 in a one year, what was the businessman's salary that year?

Answer 1

Let
`x` be the average salary of an employee. Since the salary of the business man is 6 times the average salary of an employee, his salary will be
`6x`. We also know that the sum of the salary of the businessman and the average salaries of his 10 employees is 640000, so:

`6x+10x=64000`
Solving for
`x`:

`16x=64000`

`x= (64000)/(16)`

`x=4000`
The average salary of an employee is 4000, so the salary of the businessman will be
`6*4000=24000`.

We can conclude that the business man's salary that year was 24000.