Question

If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form

Answer 1

To determine the number of moles of mercury formed when 1.20 moles of copper react with mercuric nitrate, you need to examine the balanced chemical equation. For every 2 moles of copper that react, 2 moles of mercury are formed. Therefore, if you have 1.20 moles of copper, you will also have 1.20 moles of mercury formed.

Step-by-step explanation:

In order to determine the number of moles of mercury formed when 1.20 moles of copper react with mercuric nitrate, you need to examine the balanced chemical equation for the reaction. The balanced equation is:

2Cu + Hg(NO3)2 → 2Hg + 2Cu(NO3)2

From this equation, you can see that for every 2 moles of copper (Cu) that react, 2 moles of mercury (Hg) are formed. Therefore, if you have 1.20 moles of copper, you will also have 1.20 moles of mercury formed in the reaction.

Answer 2

Reaction of Copper with Mercuric Nitrate is as follow,

Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg

According to equation,

1 Mole of Cu reacts to form = 1 Mole of Hg

So,

1.20 Moles of Cu will react to produce = X Moles of Hg

Solving for X,

X = (1.20 mol × 1 mol) ÷ 1 mol

X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.