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A college basketball player makes 5/6 of his free throws. Assuming free throws are independent, the probability that he makes it exactly three of his next four free throws is

User Ttemple
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5/6=.83 or 83%

100%-83%=16.7%

3/4=75%-16.7%=58.3%

It will 58.3% probability to make it in the bucket.
User Scotty Jamison
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