18.0k views
0 votes
The Function p(x) = x(x-5)(x-2)(x+3) has 4 zeros. What is the smallest zero?

User Boycy
by
7.9k points

1 Answer

2 votes
Answer: The smallest zero (or root) is -3

==================================================

Step-by-step explanation:

Replace p(x) with 0. Then use the zero product property to solve

p(x) = x(x-5)(x-2)(x+3)
0 = x(x-5)(x-2)(x+3)
x(x-5)(x-2)(x+3) = 0
x = 0 or x-5 = 0 or x-2 = 0 or x+3 = 0
x = 0 or x = 5 or x = 2 or x = -3

The four roots are
x = 0, x = 5, x = 2, and x = -3
these x values make p(x) equal to zero. The value x = -3 is the smallest of the list.
User Steav
by
7.7k points