Question

Which is the graph of the sequence defined by the function f(x+1)=2/3f(x) if the initial value of the sequence is 108

Answer 1

See picture attached.

Explanation:

For x = 1, f(x) = 108. For the next x-value which is 2, that is, x+1, f(x+1) = (2/3)*f(x) = (2/3)*108 = 72. For the next x-value, which is 3, f(x+1) = (2/3)*f(x) = (2/3)*72 = 48 . For the next x-value, which is 4, f(x+1) = (2/3)*f(x) = (2/3)*48 = 32 . And so on.

x f(x)

1 108

2 72

3 48

4 32