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Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation

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Define x:

Let the first number be x.

1st number = x
2nd number = x + 1
3rd number = x + 2

Construct equation:
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)

Answer: 3x + 3 = 4(x + 1)
User Dave Baghdanov
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