Question

14KMnO4 + 4C3H5(OH)3 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O How many moles of KMnO4 are consumed to form 0.886 moles of carbon dioxide?

Answer 1

2.4808 mol

Step-by-step explanation:

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Answer 2

The balanced equation is given as;
14KMnO₄ + 4C₃H₅(OH)₃ → 7K₂CO₃ + 7Mn₂O₃ + 5CO₂ + 16H₂O
14 : 5

The formed moles of CO₂ = 0.886 mol

The stoichiometric ratio between CO₂ and KMnO₄ is 5 : 14

Hence,
moles of CO₂ / moles of KMnO₄ = 5 / 14
0.886 mol / moles of KMnO₄ = 5 / 14
moles of KMnO₄ = 0.886 mol x 14 / 5
moles of KMnO₄ = 2.4808 mol

hence, consumed KMnO₄ moles = 2.4808 mol