Question

A class went on a field trip to see a play. adult tickets cost $18 each and student tickets cost $12 each. there were 10 more students than adults that went to the play. if the trip cost $240 in all, how many adults and students went to see the play?

Answer 1

To find the number of adults and students that went to see the play, we can set up equations based on the given information and solve them simultaneously. In this case, there were 4 adults and 14 students that went to see the play.

Step-by-step explanation:

To solve this problem, let's assign variables to represent the number of adults and students. Let A represent the number of adults and S represent the number of students.

From the given information, we can write two equations:

1. The cost of adult tickets ($18) multiplied by the number of adults (A) plus the cost of student tickets ($12) multiplied by the number of students (S) is equal to the total cost of the trip ($240).
2. The number of students (S) is 10 more than the number of adults (A).

Using the second equation, we can substitute A + 10 for S in the first equation:

$18A + $12(A + 10) = $240

By simplifying and solving this equation, we can find the values of A and S. In this case, A = 4 and S = 14. Therefore, there were 4 adults and 14 students that went to see the play.

Answer 2

14 students
4 adults

You can get this by making a system of equations.

x - y = 10 (number of people)
12x + 18y = 240 (cost)