Question

Find the magnitude and direction angle for the vector v=6cos137degrees i+6sin137degrees j.

A.) 6,137 degrees
B.) 6,43 degrees
C.)6squareroot of 2, 43 degrees
D.) 6squareroot of 2, 137 degrees

Answer 1

The vector in its generic form is given by:
v = lvl * (cos (theta) i + sin (theta) j)
Where,
lvl: magnitude of the vector
theta: direction angle
We have the following vector:
v = 6cos137degrees i + 6sin137degrees j.
Rewriting:
v = 6 (cos137degrees i + sin137degrees j)
Thus,
lvl = 6
theta = 137 degrees
Answer:
The magnitude and direction angle for the vector are:
A.) 6,137 degrees