Question

Please help!!!!!!!!!!!!!

Answer 1

Given => 3x + y = 10. .. equation 1

y = x - 2. ... equation 2

Putting value of y from equation 2 to equation 1, we get

=> 3x + (x - 2) = 10

=> 4x - 2 = 10

=> x = 3

Put the value of x in equation 2

=> y = 3 - 2

=> y = 1

Ans : (3, 1). (Option D)

Hope this helps!

Answer 2

`3x + y = 10 \\ 3x + (x - 2) = 10 \\ 3x + x - 2 = 10 \\ 4x - 2 = 10 \\ 4x = 12 \\ x = 3 \\ \\ 3(3) + y = 10 \\ 9 + y = 10 \\ y = 1`
(3,1)