Final answer:
The student's questions involve solving physics kinematics problems using basic kinematic equations to find velocities, displacement, and acceleration. These include calculations involving an object dropped from a height, a car's displacement under acceleration, and more.
Step-by-step explanation:
These questions are primarily related to the physics concept of kinematics, which involves the motion of objects without considering the forces causing the motion. Kinematic equations are typically used to solve these types of problems.
- To find the speed of the camera as it hits the water, we use the kinematic equation v^2 = u^2 + 2as, where u is the initial velocity (0 m/s since it's dropped), a is the acceleration due to gravity (9.81 m/s2), and s is the distance (50.0 m). Solving for v gives the camera's impact speed.
- The total displacement of a car with initial velocity v and constant acceleration a over time t can be found with s = ut + 1/2 at^2.
- Distance traveled is the product of speed and time, so multiply 20 km/h by 0.60 h for the car's displacement.
- For the skateboarder's displacement with uniform acceleration, you again use s = ut + 1/2 at^2, with u being initial velocity (0 m/s) and t being time (12 s).
- The runner's total displacement is the sum of the displacements for each part of the trip, which are products of the individual average velocities and times.
- The runner's acceleration can be derived from a = (v - u) / t or a = 2s / t^2, with s being displacement (24.6m) and t being time (3.2 s).
- To find the final velocity of the car, use v = u + at where u is the initial velocity (5 m/s), a is acceleration (0.2 m/s2), and t is time (one minute, converted to seconds).
To solve these problems, it is crucial to have a clear understanding of the basic kinematic equations and how to apply them to various scenarios.