We have the following equation:
4x2 + 3x-3 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (3) +/- root ((3) 2 - 4 (4) (- 3))) / 2 (4)
Rewriting:
x = (- 3 +/- root (9 + 48)) / 8
x = (- 3 +/- root (57)) / 8
The results are:
x = (- 3 + root (57)) / 8
x = (- 3 - root (57)) / 8
Answer:
x = (- 3 + root (57)) / 8
x = (- 3 - root (57)) / 8
option D and F