1 Answer

Grok · Answer 1 · 2019-10-15T13:02:46+0000

We assume you mean

$\ \ \display{16=4^(3x-7)}$
This is solved by writing 16 as a power of 4 and equating exponents.

$\ 4^(2)=4^(3x-7)$
2 = 3x - 7 . . . . . equate exponents
9 = 3x . . . . . add 7
3 = x . . . . . divide by 3

The solution is x = 3.

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