we know that
the distance from the centroid of the triangle to one of the vertices is the radius of the circle required to inscribe an equilateral triangle.
[distance centroid of the triangle to one of the vertices]=(2/3)*h
h=the altitude of the equilateral triangle-----> 5.196 in
so
[distance centroid of the triangle to one of the vertices]=(2/3)*5.196
[distance centroid of the triangle to one of the vertices]=3.464 in----> 3.5 in
the radius is equal to the distance of the centroid of the triangle to one of the vertices
hence
the radius is 3.5 in
the answer is
the radius is 3.5 in