Question

What is the average rate of change of the function over the interval x = 0 to x = 8?

Answer 1

Ans: The average rate of change of function =
`(1)/(102)` (in fraction)

Step-by-step explanation:
The average rate of change of function =
`(f(b) - f(a))/(b - a)`

Where
b = 8 (x's upper bound)
a = 0 (x's lower bound)


`f(b) = f(8) = (2*8-2)/(5*8-6) = (7)/(17) \\ f(a) = f(0) = (2*0-2)/(5*0-6) = (1)/(3) \\ (f(b) - f(a))/(b-a) = ( (7)/(17) - (1)/(3))/(8) = (1)/(102)`

Hence the average rate of change of function =
`(1)/(102)` (in fraction)