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What are the zero(s) of the function f(x) = the quantity of 4 x squared minus 36 x, all over x minus 9 ?

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Ans: Zero of the function is: x = 0

Step-by-step explanation:
Given function:
f(x) = (4x^2 - 36x)/(x-9)

Simplify it!
f(x) = (4x(x -9))/(x-9)
f(x) = 4x

Now Put the function equals to zero.

4x = 0
x =0 (zero of the function)
User Stefan Scherfke
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