Question

(20 pts). If g(t) = sec (t), what is g(-3 pi)?

A) -1
B) 0
C) 1
D) undefined

Answer 1

\sec t=\dfrac1{\cos t}

and

\cos(n\pi)=(-1)^n

for any integer n. With n=-3, we get \cos(-3\pi)=(-1)^{-3}=-1, so

\sec(-3\pi)=\dfrac1{-1}=-1

Answer 2

`\sec t=\frac1{\cos t}`

and


`\cos(n\pi)=(-1)^n`

for any integer
`n`. With
`n=-3`, we get
`\cos(-3\pi)=(-1)^(-3)=-1`, so


`\sec(-3\pi)=\frac1{-1}=-1`