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JasonTrue · Answer 1 · 2019-07-11T13:07:36+0000

835 g Ar to liters of Argon gas is calculated as follows

find the moles of Ar = mass/molar mass

= 835g /39.95 g/mol = 20.9 moles

At STP 1mole of ideal gas = 22.4 L, what about 20.9 moles

= 20.9 moles/1mole x 22.4 L =468.16 L of Argon

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