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What is the value of x in the equation 2/3(1//2x+12)=1/2(1/3x+14)-3

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Answer:-24


Explanation:

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User Tonny Tc
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Step 1 : 1 Simplify — 3 Equation at the end of step 1 : 2 1 1 1 (—•((—•x)+12))-((—•((—•x)+14))-3) = 0 3 2 2 3 Step 2 :Rewriting the whole as an Equivalent Fraction : 2.1 Adding a whole to a fraction

Rewrite the whole as a fraction using 3 as the denominator : 14 14 • 3 14 = —— = —————— 1 3 Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominatorAdding fractions that have a common denominator : 2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: x + 14 • 3 x + 42 —————————— = —————— 3 3 Equation at the end of step 2 : 2 1 1 (x+42) (—•((—•x)+12))-((—•——————)-3) = 0 3 2 2 3 Step 3 : 1 Simplify — 2 Equation at the end of step 3 : 2 1 1 (x+42) (—•((—•x)+12))-((—•——————)-3) = 0 3 2 2 3 Step 4 :Equation at the end of step 4 : 2 1 (x+42) (—•((—•x)+12))-(——————-3) = 0 3 2 6 Step 5 :Rewriting the whole as an Equivalent Fraction : 5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 6 as the denominator : 3 3 • 6 3 = — = ————— 1 6 Adding fractions that have a common denominator : 5.2 Adding up the two equivalent fractions
(x+42) - (3 • 6) x + 24 ———————————————— = —————— 6 6 Equation at the end of step 5 : 2 1 (x+24) (—•((—•x)+12))-—————— = 0 3 2 6 Step 6 : 1 Simplify — 2 Equation at the end of step 6 : 2 1 (x + 24) (— • ((— • x) + 12)) - ———————— = 0 3 2 6 Step 7 :Rewriting the whole as an Equivalent Fraction : 7.1 Adding a whole to a fraction

Rewrite the whole as a fraction using 2 as the denominator : 12 12 • 2 12 = —— = —————— 1 2 Adding fractions that have a common denominator : 7.2 Adding up the two equivalent fractions
x + 12 • 2 x + 24 —————————— = —————— 2 2 Equation at the end of step 7 : 2 (x + 24) (x + 24) (— • ————————) - ———————— = 0 3 2 6 Step 8 : 2 Simplify — 3 Equation at the end of step 8 : 2 (x + 24) (x + 24) (— • ————————) - ———————— = 0 3 2 6 Step 9 :Equation at the end of step 9 : (x + 24) (x + 24) ———————— - ———————— = 0 3 6 Step 10 :Calculating the Least Common Multiple : 10.1 Find the Least Common Multiple

The left denominator is : 3

The right denominator is : 6
Number of times each prime factor
appears in the factorization of:
Prime
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
31112011 Product of all
Prime Factors
366

Least Common Multiple:
6
Calculating Multipliers : 10.2 Calculate multipliers for the two fractions


Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 2

Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions : 10.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier. L. Mult. • L. Num. (x+24) • 2 —————————————————— = —————————— L.C.M 6 R. Mult. • R. Num. (x+24) —————————————————— = —————— L.C.M 6 Adding fractions that have a common denominator : 10.4 Adding up the two equivalent fractions
(x+24) • 2 - ((x+24)) x + 24 ————————————————————— = —————— 6 6 Equation at the end of step 10 : x + 24 —————— = 0 6 Step 11 :When a fraction equals zero : 11.1 When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how: x+24 ———— • 6 = 0 • 6 6 Now, on the left hand side, the 6 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
x+24 = 0Solving a Single Variable Equation : 11.2 Solve : x+24 = 0

Subtract 24 from both sides of the equation :
x = -24
One solution was found : x = -24
User Anupam Basak
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