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99 POINTS CHEMISTRY HOMEWORK

A sample of ammonia liberates 5.61 kJ of heat as it solidifies at its melting point. What is the mass of the sample? ΔHsolid = -5.66 kJ/mol.

User StudentRik
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2 Answers

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i think the answer is 5.61kJ*(1mol/5.66kJ)=0.991 mol NH3
Molar mass NH3= M(N)+3M(H)=14.0+3*1.0=17.0 g/mol
0.991 mol NH3*17.0g/1molNH3 ≈16.8 g NH3

User PaulHanak
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3 votes
5.61kJ*(1mol/5.66kJ)=0.991 mol NH3
Molar mass NH3= M(N)+3M(H)=14.0+3*1.0=17.0 g/mol
0.991 mol NH3*17.0g/1molNH3 ≈16.8 g NH3

User Matthew Gray
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